regex - PHP - how to explode a string using a comma, except situtation when this comma is inside apostrophes? -

i have following text:

$string='             blah<br>             @include (\'file_to_load\')             <br>             @include (\'file_to_load\',\'param1\',\'param2\',\'param3\')     '; 

i'd catch (and replace using preg_replace_callback) occurences of "@include" parameters (e.g. @include ('file_to_load','param1','param2','param3') )

so this:

$string='  blah<br>  @include (\'file_to_load\')  <br>  @include (\'file_to_load\',\'param1\',\'param2\') '; $params=[]; $result = preg_replace_callback(     '~@include \((,?.*?)\)~',//i catch @include, parenthesis , between them     function ($matches) {         echo '---iteration---';         $params=explode(',',$matches[1]);//exploding comma         echo '<pre>';         var_dump($params);         echo '</pre>';         return $matches[1];     },     $string ); 

and everything's fine until comma appears inside parameter, here:

$string='     blah<br>     @include (\'file_to_load\')     <br>     @include (\'file_to_load\',\'param1,something\',[\'elem\'=>\'also, comma\']]) '; 

here have comma inside "param1" param, now, after exploding explode() function doesn't work want.

i there way explode() (by using regular expression probably) string comma, not when comma inside apostrophes?

use following split:

,(?=([^']*'[^']*')*[^']*$) 

use preg_split since explode not support regex:

code:

$params = preg_split(',(?=([^']*'[^']*')*[^']*$)',$matches[1]);