neo4j - Find last node in unknown amount of relationships -


i can find last node 

match p=(a)-->(b)-->(c) a.name='object' , c:prime return c

but how find last node if don't know how many relationships -->()-->() between 2 nodes?

i trying find last node name lable name. last node doesn't have outgoing relationships.

this find c in arbitrarily long path c has not outgoing relationships.

match p=(a)-[*]->(c:prime) a.name='object'  , not( c-->() ) return c

it advisable use relationship types (if possible / practical) in query , put upward boundary on number of hops match can make. example below follows relationships of type connection in 1 direction maximum of 5 relationships.

match p=(a)-[:connection*..5]->(c:prime) a.name='object'  , not( c-->() ) return c

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